8t^2-10t-195=0

Solution for 8t^2-10t-195=0 equation:

8t^2-10t-195=0

a = 8; b = -10; c = -195;
Δ = b2-4ac
Δ = -102-4·8·(-195)
Δ = 6340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6340}=\sqrt{4*1585}=\sqrt{4}*\sqrt{1585}=2\sqrt{1585}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{1585}}{2*8}=\frac{10-2\sqrt{1585}}{16}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{1585}}{2*8}=\frac{10+2\sqrt{1585}}{16}
$